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Arithmetic Progressions (board practice) · Class 10

3 questions · English, हिन्दी, मराठी · answer key with explanations · 12 October 2026

NCERT: Class 10 Mathematics, Chapter 5: Arithmetic Progressions. Our own questions in the chapter's style, drafted with AI help, every answer checked step by step; teacher review pending. Hindi and Marathi: translation - review pending.

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Arithmetic Progressions (board practice) · English

Name: ____________________Date: ____________

Questions

Find the 20th term of the AP 7, 11, 15, ...
Add up the first 15 terms of the AP 3, 5, 7, ... What is the total?
Which term of the AP 5, 9, 13, ... is 81?

Answer key

83 — a = 7, d = 4; a₂₀ = a + 19d = 7 + 76 = 83.
255 — Sₙ = n/2 × (2a + (n − 1)d) = 15/2 × (6 + 28) = 255.
20 — 5 + (n − 1) × 4 = 81, so n − 1 = 19 and n = 20.

समांतर श्रेढ़ियाँ (बोर्ड अभ्यास) · हिन्दी

नाम: ____________________तारीख़: ____________

प्रश्न

समांतर श्रेढ़ी 7, 11, 15, ... का 20वाँ पद ज्ञात करो।
3, 5, 7, ... के पहले 15 पदों का योग ज्ञात करो।
समांतर श्रेढ़ी 5, 9, 13, ... का कौन-सा पद 81 है?

उत्तर

83 — a = 7, d = 4; a₂₀ = a + 19d = 7 + 76 = 83।
255 — Sₙ = n/2 × (2a + (n − 1)d) = 15/2 × (6 + 28) = 255।
20 — 5 + (n − 1) × 4 = 81, तो n − 1 = 19 और n = 20।

अंकगणितीय श्रेढी (बोर्ड सराव) · मराठी

नाव: ____________________दिनांक: ____________

प्रश्न

अंकगणितीय श्रेढी 7, 11, 15, ... चे 20 वे पद काढा.
3, 5, 7, ... च्या पहिल्या 15 पदांची बेरीज काढा.
अंकगणितीय श्रेढी 5, 9, 13, ... चे कितवे पद 81 आहे?

उत्तरे

83 — a = 7, d = 4; a₂₀ = a + 19d = 7 + 76 = 83.
255 — Sₙ = n/2 × (2a + (n − 1)d) = 15/2 × (6 + 28) = 255.
20 — 5 + (n − 1) × 4 = 81, म्हणून n − 1 = 19 आणि n = 20.

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