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Linear Polynomials · Class 9

5 questions · English, हिन्दी, मराठी · answer key with explanations ·

NCERT: Class 9 Ganita Manjari Part I, Chapter 2: Introduction to Linear Polynomials. Our own questions in the chapter's style, drafted with AI help, every answer checked step by step; teacher review pending. Hindi and Marathi: translation - review pending.

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Linear Polynomials · English

Name: ____________________Date: ____________

Questions

  1. For p(x) = 3x − 6, find the zero of p(x) (the value of x for which p(x) = 0).

  2. If p(x) = 2x + 7, what is p(4)?

  3. Find the zero of p(x) = 5x + 20.

  4. If p(x) = 4x − 3, what is p(−2)?

  5. For which value of k does the graph of p(x) = kx − 12 cut the x-axis at x = 3?

Answer key

  1. 2 — 3x − 6 = 0, so 3x = 6 and x = 2.
  2. 15 — Put x = 4: 2 × 4 + 7 = 15.
  3. -4 — 5x + 20 = 0, so 5x = −20 and x = −4.
  4. -11 — Put x = −2: 4 × (−2) − 3 = −8 − 3 = −11.
  5. 4 — Where the graph cuts the x-axis, p(x) = 0. So 3k − 12 = 0 and k = 4.

रैखिक बहुपद · हिन्दी

नाम: ____________________तारीख़: ____________

प्रश्न

  1. p(x) = 3x − 6 का शून्यक ज्ञात करो (x का वह मान जिस पर p(x) = 0)।

  2. अगर p(x) = 2x + 7 है, तो p(4) कितना है?

  3. p(x) = 5x + 20 का शून्यक ज्ञात करो।

  4. अगर p(x) = 4x − 3 है, तो p(−2) कितना है?

  5. k के किस मान पर p(x) = kx − 12 का आलेख x-अक्ष को x = 3 पर काटता है?

उत्तर

  1. 2 — 3x − 6 = 0, तो 3x = 6 और x = 2।
  2. 15 — x = 4 रखो: 2 × 4 + 7 = 15।
  3. -4 — 5x + 20 = 0, तो 5x = −20 और x = −4।
  4. -11 — x = −2 रखो: 4 × (−2) − 3 = −8 − 3 = −11।
  5. 4 — जहाँ आलेख x-अक्ष को काटता है, वहाँ p(x) = 0। तो 3k − 12 = 0 और k = 4।

रेषीय बहुपदी · मराठी

नाव: ____________________दिनांक: ____________

प्रश्न

  1. p(x) = 3x − 6 ची शून्य किंमत शोधा (x ची अशी किंमत जिथे p(x) = 0).

  2. जर p(x) = 2x + 7 असेल, तर p(4) किती?

  3. p(x) = 5x + 20 ची शून्य किंमत काढा.

  4. जर p(x) = 4x − 3 असेल, तर p(−2) किती?

  5. k च्या कोणत्या किमतीसाठी p(x) = kx − 12 चा आलेख x-अक्षाला x = 3 वर छेदतो?

उत्तरे

  1. 2 — 3x − 6 = 0, म्हणून 3x = 6 आणि x = 2.
  2. 15 — x = 4 ठेवा: 2 × 4 + 7 = 15.
  3. -4 — 5x + 20 = 0, म्हणून 5x = −20 आणि x = −4.
  4. -11 — x = −2 ठेवा: 4 × (−2) − 3 = −8 − 3 = −11.
  5. 4 — जिथे आलेख x-अक्षाला छेदतो तिथे p(x) = 0. म्हणून 3k − 12 = 0 आणि k = 4.

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