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Class 9 Maths: Measuring Space, Perimeter and Area, 8 practice questions with answers
These are 8 practice questions on Chapter 6, Measuring Space: Perimeter and Area, of the new NCERT Class 9 Maths textbook, Ganita Manjari, Part I (First Edition, April 2026). Each has a worked answer, the units, and the textbook page it comes from. They cover the perimeter of a rectangle, the circumference and area of a circle, a rolling wheel, and Heron's formula for a triangle and for a four-sided figure. Try each one on paper before you open the answer. The surface area and volume of a cuboid and a cylinder are in the Class 9 Surface Area and Volume questions.
These questions are our own, drafted with AI help. Every number was re-computed by a test script, but no practising teacher has reviewed them yet. If you find a mistake, please tell us.
What the chapter says you need
Facts from the NCERT textbook (Ganita Manjari: Mathematics, Textbook for Grade 9, Part I, Chapter 6, printed pages 118 to 154):
- The perimeter of a rectangle with length a and width b is 2(a + b) (page 119).
- π is not equal to 22/7. The fraction 22/7 is good enough for most practical uses, but the textbook stresses that the two are "close but not equal", and writes π ≈ 22/7 and also π ≠ 22/7 (page 124).
- The circumference of a circle of radius r is 2πr (page 125). The area of a circle is A = πr² (pages 145 and 146; summary, page 154).
- Heron's formula (section 6.8.1, page 134): with semi-perimeter s = half the perimeter, the area of a triangle with sides a, b and c is √(s(s − a)(s − b)(s − c)). Worked examples are on pages 135 and 136.
- The area of a four-sided figure (a 4-gon) cannot be found from its four sides alone: you need more information, such as the length of one diagonal (page 137). Splitting the figure along a diagonal into two triangles and using Heron's formula on each is our own step.
Perimeter and the circle
Question 1. A rectangular field is 40 m long and 25 m wide. What is its perimeter in m?
Answer: 130 m. Perimeter = 2 × (length + width) = 2 × 65 = 130 m. (Page 119.)
Question 2. Meera runs once around a circular track of radius 35 m. Ravi runs once around a square track of side 55 m. Using 22/7 for π, who runs farther?
Answer: they run the same distance, 220 m. One round of the circle is its circumference: 2πr = 2 × 22/7 × 35 = 220 m. One round of the square is its perimeter: 4 × 55 = 220 m. So neither runs farther. (Circumference of a circle and the approximation 22/7, pages 124 and 125; perimeter of a square, page 119.)
Question 3. A circle has a radius of 14 cm. Using 22/7 for π, what is its area in square cm?
Answer: 616 cm². Area = πr² = 22/7 × 14 × 14 = 22 × 2 × 14 = 616 square cm. (The true value is about 615.75 cm²; pages 124 and 145.)
Question 4. A wheel of radius 35 cm makes 10 full turns. Using 22/7 for π, how far does it roll, in cm?
Answer: 2,200 cm. One turn = the circumference = 2 × 22/7 × 35 = 220 cm. Ten turns = 2,200 cm. (The true value is about 2,199.1 cm. Circumference, page 125; the textbook's own tyre exercise, which asks how far a car travels for one revolution of the tyre, is Exercise Set 6.1, question 6, page 130.)
Heron's formula
Heron's formula: area = √(s(s − a)(s − b)(s − c)), where s is half the perimeter (page 134).
Question 5. A triangle has sides 5 cm, 5 cm and 6 cm. Using Heron's formula, what is its area in square cm?
Answer: 12 cm². s = (5 + 5 + 6) ÷ 2 = 8; area = √(8 × 3 × 3 × 2) = √144 = 12 square cm. (Page 134; the textbook treats the isosceles case on page 135.)
Question 6. Use Heron's formula to find the area of a triangle with sides 13 cm, 14 cm and 15 cm, in square cm.
Answer: 84 cm². Semi-perimeter s = (13 + 14 + 15) ÷ 2 = 21. Heron's formula multiplies s by s − 13, s − 14 and s − 15, then takes the square root: √(21 × 8 × 7 × 6) = √7056 = 84 square cm. (Page 134.)
Question 7. A triangle has sides 7 cm, 15 cm and 20 cm. Find its area in square cm using Heron's formula. (This question is not in the practice set.)
Answer: 42 cm². s = (7 + 15 + 20) ÷ 2 = 21. Area = √(21 × 14 × 6 × 1) = √1764 = 42 square cm. (Page 134.)
Question 8. In the quadrilateral ABCD, AB = 3 cm, BC = 4 cm, CD = 5 cm, DA = 6 cm and the diagonal AC = 5 cm; the diagonal AC lies inside ABCD. Using Heron's formula for the two triangles, find the area of ABCD, in square cm.
Answer: 18 cm². The diagonal AC splits ABCD into triangles ABC (3, 4, 5) and ACD (5, 5, 6). Triangle ABC: s = 6, area = √(6 × 3 × 2 × 1) = 6. Triangle ACD: s = 8, area = √(8 × 3 × 3 × 2) = √144 = 12. Area of ABCD = 6 + 12 = 18 square cm. (Heron's formula, page 134; a four-sided figure needs a diagonal besides its four sides, page 137.)
Practise more, and check your marks
- Free practice, marked instantly in your browser: Class 9 Measuring Space: Perimeter and Area questions. Questions 1, 3 to 6 and 8 above are in this set. Their wording is the same as in the set, with three differences: in questions 3 and 4 the practice tool says "Taking π = 22/7" where this page says "Using 22/7 for π" (the textbook stresses that π is not equal to 22/7), and in question 8 this page adds "the diagonal AC lies inside ABCD". Questions 2 and 7 are new on this page.
- Printable worksheet with answer key, in English, Hindi and Marathi: Class 9 Measuring Space worksheet.
- The Class 10 follow-ups: Areas Related to Circles and Surface Areas and Volumes.
- The first chapter of this Class 9 book: Ganita Manjari Class 9 Chapter 1, coordinates, explained.
Where CMDLearn fits
CMDLearn is building an AI tutor for Classes 1 to 10 that explains a step and checks the child's working, but leaves the writing to the child. It is still in development, and no child uses it yet. If you would like to hear when there is something to try, you can join the waitlist.
Sources
All opened and read on 21 October 2026. Page numbers are the printed page numbers of the textbook; printed page = PDF page + 117.
- NCERT, Ganita Manjari: Textbook of Mathematics for Grade 9, Part I (First Edition, April 2026), Chapter 6 "Measuring Space: Perimeter and Area", printed pages 118-154 (perimeter of a rectangle, page 119; π and 22/7, page 124; circumference, page 125; Exercise Set 6.1, question 6, on a car tyre, page 130; Heron's formula, section 6.8.1, page 134; worked examples, pages 135-136; the 4-gon needs more than its sides, page 137; area of a circle, pages 145-146; chapter summary, page 154): ncert.nic.in/textbook/pdf/iemh106.pdf
- NCERT, Ganita Manjari: Textbook of Mathematics for Grade 9, Part I, front matter and contents (chapter titles and starting pages): ncert.nic.in/textbook/pdf/iemh1ps.pdf
The formulas and definitions are from the textbook pages above. The questions, worked answers and checks are our own, and every number was re-computed by script. This guide is general information; follow your teacher and the textbook.