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Class 8 Maths: Area, 8 practice questions with answers
These are 8 practice questions on Chapter 7, Area, of the new NCERT Class 8 Maths textbook, Ganita Prakash, Part 2. Each has a worked answer and the textbook page it comes from. They cover tiles for a floor, an L-shaped room, a triangle whose base doubles while its height halves, one fence that shares a field equally, a five-sided wall split into simpler pieces, a parallelogram's height from its slanting side, a rhombus from its side and one diagonal, and two trapezium beds whose parallel sides add up to the same length. Try each one on paper before you open the answer.
These questions are our own, drafted with AI help. Every answer was re-worked by a test script and each question was compared with the chapter's examples, activities and exercises, but no practising teacher has reviewed them yet. If you find a mistake, please tell us.
What the chapter says you need
Facts from the NCERT textbook (Ganita Prakash, Grade 8, Part 2, Chapter 7, printed pages 148 to 171):
- Area counts unit squares: a rectangle's area is length × width, and two shapes with the same perimeter can have different areas (pages 149 and 150).
- A triangle's area is half of base × height, for every kind of triangle, and any side can be the base if its own height is used (pages 153 to 155).
- The line from a corner of a triangle to the midpoint of the side facing it cuts the triangle into two parts of equal area, and any polygon can be cut into triangles (pages 155 and 159).
- A parallelogram's area is base × height; a rhombus's is half the product of its diagonals; a trapezium's is half the height times the sum of its parallel sides (pages 161 to 169).
- One inch is 2.54 cm, so one square inch is 6.4516 square cm (pages 170 and 171).
Rectangles and borders
Question 1. A floor 3 m long and 2 m wide is to be covered with square tiles of side 25 cm, with no gaps and no cutting. How many tiles are needed?
Answer: 96 tiles. 3 m = 300 cm and 2 m = 200 cm. Along the length, 300 ÷ 25 = 12 tiles fit in a row, and along the width 200 ÷ 25 = 8 rows, so the floor takes 12 × 8 = 96 tiles. (Unit squares filling a rectangle, length × width, page 149.)
Question 2. An L-shaped room is a rectangle 8 m by 6 m with a 3 m by 2 m rectangle missing from one corner. Find its area in two different ways.
Answer: 42 square m. Way 1: the full rectangle is 8 × 6 = 48 square m; take away the missing corner, 3 × 2 = 6 square m: 48 − 6 = 42 square m. Way 2: cut the L into two rectangles. If the 3 m by 2 m gap is along the 8 m side, one piece is the full 8 m by 4 m strip (32 square m) and the other is the 5 m by 2 m piece beside the gap (10 square m): 32 + 10 = 42 square m. Both ways agree. (Areas built from rectangles, page 149.)
Triangles
Question 3. A triangular plot has a side of 12 m, and the height to that side is 7 m. Its area is 42 square m. A second plot has a base twice as long, 24 m, and a height half as long, 3.5 m. How does its area compare with the first plot's, and why?
Answer: the same, 42 square m. Area = 1/2 × 24 × 3.5 = 42 square m, the same. Doubling the base doubles the area and halving the height halves it, so together they leave it unchanged. (The area of a triangle, pages 153 to 155.)
Question 4. Two brothers are to share a triangular field of area 54 square m equally, using one straight fence that starts at one corner. Where must the other end of the fence be, and why are the two pieces then equal?
Answer: at the midpoint of the side facing that corner; each piece is then 27 square m. The fence splits the field into two triangles with the same height, measured from the corner to the facing side. Their bases are the two parts of that side. Equal bases with the same height give equal areas, so the fence must end at the midpoint of the facing side, and each brother gets 54 ÷ 2 = 27 square m. (A line from a corner to the midpoint of the opposite side, page 155.)
Polygons and quadrilaterals
Question 5. The front wall of a small house is a rectangle 10 m wide and 6 m tall, with a triangular part on top whose base is the 10 m top edge and whose height is 4 m. What is the area of the whole five-sided wall?
Answer: 80 square m. Cut the pentagon into the pieces whose areas are known: the rectangle is 10 × 6 = 60 square m and the triangle is 1/2 × 10 × 4 = 20 square m, so the wall is 60 + 20 = 80 square m. Any polygon can be cut into triangles (the rectangle itself is two triangles of 30 square m), so this always works. (The area of any polygon, page 159.)
Question 6. A parallelogram has a base of 15 cm and a slanting side of 10 cm whose top end is 6 cm to the right of its bottom end. Find its height and its area.
Answer: height 8 cm, area 120 square cm. The slanting side, the height and the 6 cm shift make a right triangle with the 10 cm side as its longest side, so the height is the square root of 100 − 36 = 64, that is 8 cm. The area is base × height = 15 × 8 = 120 square cm. (The area of a parallelogram, base × height, pages 161 to 163; the right-triangle step uses the Baudhayana-Pythagoras theorem from Chapter 2 of this book.)
Question 7. A rhombus has sides of 10 cm, and one of its diagonals is 12 cm. Find the other diagonal, and hence the area of the rhombus.
Answer: 16 cm, and an area of 96 square cm. The diagonals of a rhombus cut each other in half at right angles. So half of the 12 cm diagonal (6 cm), half of the other diagonal and a 10 cm side make a right triangle with the side as its longest side. By the Baudhayana theorem, the half-diagonal is the square root of 100 − 36 = 64, that is 8 cm, so the other diagonal is 16 cm. Then the area = 1/2 × 12 × 16 = 96 square cm. Check: the 4 small triangles each have area 1/2 × 6 × 8 = 24, and 4 × 24 = 96. (The area of a rhombus from its diagonals, pages 164 and 165; the right-triangle step uses the Baudhayana-Pythagoras theorem from Chapter 2 of this book.)
Question 8. Two garden beds are trapeziums, both with their parallel sides 4 m apart. Bed A's parallel sides are 9 m and 5 m; bed B's are 8 m and 6 m. Without drawing them, which bed has the larger area? What do all trapeziums with height 4 m and parallel sides adding up to 14 m have in common?
Answer: they have the same area, 28 square m; every such trapezium has area 28 square m. A trapezium's area is half the height times the sum of the parallel sides. For bed A that is 1/2 × 4 × (9 + 5) = 28, and for bed B 1/2 × 4 × (8 + 6) = 28: equal. Since only the sum of the parallel sides (with the height) matters, every trapezium with height 4 m and parallel sides adding up to 14 m has area 28 square m, however the 14 m is split. (The area of a trapezium, pages 166 to 168.)
Practise more, and check your marks
- Free practice, marked instantly in your browser: Class 8 practice questions, a short set for each chapter.
- Printable worksheets with answer keys, in English, Hindi and Marathi: all the Class 8 worksheets.
- Parallelograms, rhombuses and trapeziums and their properties: Class 8 Quadrilaterals.
- The theorem used for the rhombus side in Question 7: Class 8 The Baudhayana-Pythagoras Theorem.
- Where area leads in Class 9: Class 9 Measuring Space: Perimeter and Area.
Where CMDLearn fits
CMDLearn is building an AI tutor for Classes 1 to 10 that explains a step and checks the child's working, but leaves the writing to the child. It is still in development, and no child uses it yet. If you would like to hear when there is something to try, you can join the waitlist.
Sources
All opened and read on 31 October 2026. Page numbers are the printed page numbers of the textbook; printed page = PDF page + 147.
- NCERT, Ganita Prakash: Textbook of Mathematics for Grade 8, Part 2 (First Edition December 2025), Chapter 7 "Area", printed pages 148-171 (rectangles and squares, pages 148-152; triangles, pages 153-159; the area of any polygon, pages 159-160; parallelograms, pages 161-164; the rhombus, pages 164-166; the trapezium, pages 166-170; areas in real life and units, pages 170-171; summary, page 171): ncert.nic.in/textbook/pdf/hegp207.pdf
- NCERT, Ganita Prakash, Grade 8, Part 2, front matter and contents (edition line, chapter list and starting pages): ncert.nic.in/textbook/pdf/hegp2ps.pdf
The rules are from the textbook pages above. The questions, worked answers and checks are our own, and every number was re-computed by script. This guide is general information; follow your teacher and the textbook.
Practise with the worksheet: Area, Class 8 worksheet. Printable, in English, Hindi and Marathi, with an answer key.