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Class 10 Triangles: 8 practice questions with answers, step by step

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These are 8 practice questions on NCERT Class 10 Maths Chapter 6, Triangles, each with a worked answer. They cover what the chapter asks: finding a missing side of similar triangles, using the basic proportionality theorem and its converse, and deciding whether two triangles are similar by AA, SSS or SAS. Try each one on paper before you open the answer. Another Class 10 geometry set, on tangents to a circle, is Class 10 Circles.

These questions are our own, drafted with AI help. Every answer was re-computed by a test script, but no practising teacher has reviewed them yet. If you find a mistake, please tell us.

What the chapter says you need

Six facts from the NCERT textbook (Mathematics, Textbook for Class X, Reprint 2026-27, Chapter 6, printed pages 73 to 98) cover every question below:

Similar triangles and missing sides

Question 1. Triangles ABC and PQR are similar, with AB = 4 cm, PQ = 6 cm and BC = 8 cm. Find QR in cm.

Answer: Corresponding sides are in the same ratio: QR/BC = PQ/AB = 6/4. So QR = 8 × 6/4 = 12 cm.

Question 2. A 6 m pole has a 4 m shadow. A tower nearby has a 28 m shadow at that moment. How tall is the tower, in m?

Answer: The sun makes similar triangles with the pole and with the tower, so height ÷ shadow is the same: 6 ÷ 4 = h ÷ 28, and h = 6 × 28 ÷ 4 = 42 m.

The basic proportionality theorem and its converse

Question 3. In triangle ABC, DE ∥ BC, with AD = 3 cm, DB = 6 cm and AE = 2 cm. Find EC in cm.

Answer: By the basic proportionality theorem, AD/DB = AE/EC: 3/6 = 2/EC, so EC = 2 × 6 ÷ 3 = 4 cm.

Question 4. In triangle ABC, D is on AB and E is on AC, with AD = 4 cm, DB = 6 cm and AE = 6 cm. How long must EC be, in cm, for DE to be parallel to BC?

Answer: By the converse, DE ∥ BC when AD/DB = AE/EC: 4/6 = 6/EC, so EC = 6 × 6 ÷ 4 = 9 cm.

Question 5. In triangle ABC, DE ∥ BC with AD = 2 cm, AB = 6 cm and BC = 9 cm. Find DE in cm.

Answer: Triangle ADE is similar to triangle ABC (the parallel line makes equal corresponding angles), so DE ÷ BC = AD ÷ AB = 2 ÷ 6. DE = 9 × 2 ÷ 6 = 3 cm.

Which criterion proves similarity?

Question 6. In triangles ABC and DEF, ∠A = ∠D = 50° and ∠B = ∠E = 60°. Are the triangles similar? Which criterion do you use?

Answer: yes, by the AA criterion. Two angles of one triangle equal two angles of the other. (The third angles are also equal: ∠C = 180° − 50° − 60° = 70° and ∠F = 70°, so this is the AAA situation too.)

Question 7. The sides of triangle ABC are 3 cm, 4 cm and 5 cm. The sides of triangle DEF are 6 cm, 8 cm and 10 cm. Are the triangles similar? Which criterion do you use?

Answer: yes, by the SSS criterion. Compare the sides in order: 3/6 = 1/2, 4/8 = 1/2 and 5/10 = 1/2. All three ratios are equal, so the triangles are similar.

Question 8. In triangles ABC and PQR, ∠A = ∠P = 40°, AB = 4 cm, AC = 6 cm, PQ = 6 cm and PR = 9 cm. Are the triangles similar? Which criterion do you use?

Answer: yes, by the SAS criterion. The equal angles are ∠A and ∠P, and the sides including them are proportional: AB/PQ = 4/6 = 2/3 and AC/PR = 6/9 = 2/3. So triangle ABC is similar to triangle PQR.

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Sources

All opened and read on 21 October 2026. Page numbers are the printed page numbers of the textbook.

The theorems and criteria are from the textbook pages above. The questions, worked answers and checks are our own, and every number was re-computed by script. This guide is general information; follow your teacher and the official CBSE notices.