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Class 10 Science: Light, Reflection and Refraction, 8 practice questions with answers
These are 8 practice questions on NCERT Class 10 Science Chapter 9, Light: Reflection and Refraction, each with a worked answer and the textbook page it comes from. Two are mirror formula numericals and one is a lens formula numerical; the rest cover the radius of curvature, power, refractive index and a rear-view mirror. Try each one on paper before you read the answer. Reflection is not only for light: sound reflects too, and echoes are in the Class 9 Sound Waves questions.
These questions are our own, drafted with AI help. Every number was re-computed by a test script, but no practising teacher has reviewed them yet. If you find a mistake, please tell us.
The formulas and the sign convention
Facts from the NCERT textbook (Science, Textbook for Class X, Reprint 2026-27, Chapter 9, printed pages 134 to 160):
- For a spherical mirror of small aperture, the radius of curvature is twice the focal length: R = 2f (page 137).
- Distances are measured with the New Cartesian Sign Convention: from the pole of the mirror (or the optical centre of the lens), distances along the direction of the incident light are positive and against it are negative (page 142).
- Mirror formula: 1/v + 1/u = 1/f, valid for all spherical mirrors and all object positions (page 143). Magnification by a mirror is m = h′/h = −v/u (pages 143 and 144).
- Lens formula: 1/v − 1/u = 1/f (page 155). The focal length of a convex lens is positive and that of a concave lens is negative (page 155). Magnification by a lens is m = h′/h = v/u (page 156).
- Power of a lens is the reciprocal of its focal length, P = 1/f, with f in metres; its SI unit is the dioptre (D) (pages 157 and 158). The net power of lenses placed in contact is the algebraic sum of their powers, P = P₁ + P₂ + … (page 158).
- The refractive index of a transparent medium is the ratio of the speed of light in vacuum to its speed in the medium (summary, page 159).
Mirrors
Question 1. A concave mirror has a radius of curvature of 30 cm. How far is its focus from the mirror, in cm?
Answer: 15 cm. Focal length = radius of curvature ÷ 2 = 30 ÷ 2 = 15 cm. By the sign convention a concave mirror's focal length is written −15 cm. (R = 2f, page 137.)
Question 2. A concave mirror has a focal length of 15 cm. A candle stands 30 cm in front of it. How far from the mirror is the image formed?
Answer: 30 cm in front of the mirror. Use 1/v + 1/u = 1/f with u = −30 cm and f = −15 cm: 1/v = −1/15 + 1/30 = −1/30, so v = −30 cm. The image forms 30 cm in front of the mirror, at the centre of curvature. (Mirror formula, page 143.)
Question 3. A concave mirror has a focal length of 20 cm. An object 5 cm tall stands 30 cm from it. How tall is the image, in cm?
Answer: 10 cm, inverted. With u = −30 cm and f = −20 cm: 1/v = −1/20 + 1/30 = −1/60, so v = −60 cm. Magnification m = −v/u = −(−60)/(−30) = −2. Image height = m × 5 = −10 cm, which means 10 cm tall and inverted. (Mirror formula and magnification, pages 143-144.)
Question 4. Why is a convex mirror used as the rear-view mirror of a vehicle?
Answer: A convex mirror always gives an erect, though diminished, image, and it has a wider field of view, so the driver can see more of the traffic behind. (Uses of convex mirrors, page 142.)
Lenses and refraction
Question 5. A convex lens has a focal length of 10 cm. An object 4 cm tall is placed 15 cm from it. How tall is the image, in cm?
Answer: 8 cm, inverted. With u = −15 cm and f = +10 cm: 1/v − 1/u = 1/f gives 1/v = 1/10 − 1/15 = 1/30, so v = +30 cm. Magnification m = v/u = 30/(−15) = −2. Image height = −2 × 4 = −8 cm: 8 cm tall and inverted. (Lens formula, page 155; lens magnification, page 156.)
Question 6. A convex lens has a focal length of 50 cm. What is its power, in dioptres?
Answer: +2 D. Power P = 1/f with f in metres: f = 50 cm = 0.5 m, so P = 1/0.5 = +2 D (positive for a convex lens). (Pages 157-158.)
Question 7. Two thin lenses of power +2.5 D and −0.5 D are placed in contact. What is the focal length of the combination, in cm?
Answer: 50 cm. Powers of lenses in contact add: P = 2.5 + (−0.5) = 2 D. Focal length f = 1/P = 1/2 m = 0.5 m = 50 cm, a converging combination. (Page 158.)
Question 8. Light travels at 3 × 10⁸ m/s in air and at 2 × 10⁸ m/s in a kind of glass. What is the refractive index of this glass with respect to air?
Answer: 1.5. Refractive index = speed of light in air ÷ speed of light in the glass = (3 × 10⁸) ÷ (2 × 10⁸) = 1.5. It has no unit. (The textbook defines refractive index through the speed of light in vacuum; summary, page 159. Air is taken as very nearly the same as vacuum for this question.)
Practise more, and check your marks
- Free practice, marked instantly in your browser: Class 10 Science board questions. There is no separate light topic; this set mixes Class 10 Science questions, and the light ones (including questions 1, 2, 3, 5, 6, 7 and 8 above) are among them.
- Printable worksheets with answer keys, in English, Hindi and Marathi: Class 10 worksheets.
- How the chapter fits the board paper: our Class 10 Science syllabus 2026-27 guide and the sample paper, section by section.
- Another chapter of the same unit set: NCERT Class 10 Science Chapter 11, Electricity.
Where CMDLearn fits
CMDLearn is building an AI tutor for Classes 1 to 10 that explains a step and checks the child's working, but leaves the writing to the child. It is still in development, and no child uses it yet. If you would like to hear when there is something to try, you can join the waitlist.
Sources
All opened and read on 21 October 2026. Page numbers are the printed page numbers of the textbook.
- NCERT, Science, Textbook for Class X, Chapter 9 "Light: Reflection and Refraction" (Reprint 2026-27), printed pages 134-160 (R = 2f, page 137; the New Cartesian Sign Convention and convex mirrors as rear-view mirrors, page 142; the mirror formula and magnification, pages 143-144; the lens formula and the signs of focal length, page 155; lens magnification, page 156; power, pages 157-158; the refractive index, summary, page 159): ncert.nic.in/textbook/pdf/jesc109.pdf
The formulas and definitions are from the textbook pages above. The questions, worked answers and checks are our own, and every number was re-computed by script. This guide is general information; follow your teacher and the textbook.