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Class 10 Light notes: NCERT Science Chapter 9, Reflection and Refraction

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These are short revision notes for Chapter 9 of the NCERT Class 10 Science textbook, "Light – Reflection and Refraction" (Reprint 2026-27), pages 134 to 160. The chapter has two formulas that look alike and one sign convention that decides most marks, so these notes put the formulas side by side, then go through mirrors and lenses section by section, and end with the key words, the ray diagram to practise, the common mistakes and 8 quick questions of our own with worked answers.

Keep the textbook open next to these notes. The wording here is our own; the textbook is the authority.

How much it counts

CBSE's Class 10 Science curriculum for 2026-27 puts this chapter in Unit III, Natural Phenomena, worth 12 of the 80 theory marks, shared with The Human Eye and the Colourful World (curriculum, PDF page 4). For this chapter the unit lists reflection from curved surfaces, the images spherical mirrors form and the terms used for them, the mirror formula (no derivation), magnification, refraction and its laws, refractive index, images formed by spherical lenses, the lens formula (no derivation), magnification and the power of a lens (PDF page 5). More on the units: CBSE Class 10 Science syllabus 2026-27.

The formulas on one page

QuantityMirrorLensPage
Focal length and radiusR = 2f(not used in Class 10)137
Formula1/v + 1/u = 1/f1/v − 1/u = 1/f143, 155
Magnificationm = h′/h = −v/um = h′/h = v/u143, 156
Refractive indexn₂₁ = v₁/v₂; for a medium, n = c/v148-149
PowerP = 1/f (f in metres), unit dioptre (D)157-158
Lenses in contactP = P₁ + P₂ + P₃ + …158

1. Reflection and spherical mirrors (sections 9.1-9.2, pages 134-137)

2. Images by mirrors (pages 138-142)

Concave mirror (Table 9.1, page 138):

ObjectImageSizeNature
At infinityAt FHighly diminished, point-sizedReal, inverted
Beyond CBetween F and CDiminishedReal, inverted
At CAt CSame sizeReal, inverted
Between C and FBeyond CEnlargedReal, inverted
At FAt infinity——
Between P and FBehind the mirrorLarger than the objectVirtual, erect

Convex mirror (Table 9.2, page 141): the image is always behind the mirror, between P and F (at F for an object at infinity), diminished, virtual and erect.

Rays for diagrams (pages 138-139): a ray parallel to the axis passes through F after reflection (concave) or seems to come from F (convex); a ray through F, or aimed at F, comes back parallel; a ray through C, or aimed at C, returns along itself; a ray striking P reflects at an equal angle to the axis.

Uses:

3. Sign convention, mirror formula and magnification (pages 142-145)

New Cartesian Sign Convention (pages 142-143):

So u is negative for a real object; f is negative for a concave mirror and positive for a convex one.

Mirror formula: 1/v + 1/u = 1/f, valid for every spherical mirror and every object position (page 143).

Magnification: m = h′/h = −v/u. A negative m means a real (inverted) image, and a positive m means a virtual (erect) image (page 143).

4. Refraction (section 9.3, pages 145-149)

5. Lenses, lens formula and power (pages 150-158)

Key words at a glance

The diagram to know: convex lens, object between F₁ and 2F₁

Board papers often ask for one lens ray diagram. Practise this one (it is one of the cases in Fig. 9.16):

  1. Draw the principal axis and the lens at O; mark F₁ and 2F₁ on the left, F₂ and 2F₂ on the right, at equal spacing.
  2. Draw the object as an upright arrow between F₁ and 2F₁.
  3. From the top of the object, draw a ray parallel to the axis; after the lens, draw it through F₂.
  4. From the same point, draw a ray through O, carrying straight on.
  5. Where the two rays meet, beyond 2F₂, draw the image as an inverted arrow, larger than the object. Label it real, inverted, enlarged.

Mistakes that cost marks

Quick check: 8 questions of our own

These are our own questions, written for these notes and checked against the textbook pages named; no practising teacher has reviewed them yet. Every number was re-computed by a script.

Question 1. A concave mirror has a focal length of 12 cm. A 2 cm tall pin stands upright 8 cm away from it. (a) Write u and f with their signs. (b) Find the image distance. (c) Find the magnification and the image height. (d) Describe the image, and check it against the textbook's table.

Answer: (a) u = −8 cm, f = −12 cm; (b) v = +24 cm, behind the mirror; (c) m = +3, h′ = +6 cm; (d) virtual, erect, enlarged. (a) The object is on the left, and a concave mirror's focus is in front of it, so both are negative (pages 142-143). (b) 1/v = 1/f − 1/u = −1/12 + 1/8 = (−2 + 3)/24 = 1/24, so v = +24 cm. (c) m = −v/u = −24/(−8) = +3, so h′ = 3 × 2 = 6 cm (page 143). (d) A positive m means a virtual, erect image; Table 9.1 gives exactly this for an object between P and F (page 138).

Question 2. A convex mirror on a shop wall has a radius of curvature of 40 cm. A customer stands 30 cm in front of it. (a) What is its focal length, with sign? (b) Where is the image? (c) What is the magnification, and what is the image like?

Answer: (a) +20 cm; (b) 12 cm behind the mirror; (c) +0.4, virtual, erect and diminished. (a) f = R/2 = 40/2 = 20 cm, positive because a convex mirror's focus is behind it (pages 137, 143). (b) 1/v = 1/f − 1/u = 1/20 + 1/30 = 5/60 = 1/12, so v = +12 cm. (c) m = −v/u = −12/(−30) = +0.4. That fits Table 9.2: the image sits behind the mirror, between P and F, smaller than the object, virtual and erect (page 141).

Question 3. Say which mirror is needed, and where the object must be, in each case: (a) a sharp image of a candle the same size as the candle, inverted, on a screen; (b) a large, erect image of a tooth; (c) a mirror on a sharp hill bend that always shows an erect view of a wide stretch of road; (d) a real image of a distant streetlight formed as a tiny bright point.

Answer: (a) concave mirror, object at C; (b) concave mirror, object between P and F; (c) convex mirror; (d) concave mirror, image at F. (a) and (b) are rows of Table 9.1 (page 138); dentists use concave mirrors for (b) (page 140). (c) A convex mirror always gives an erect, diminished image and has a wider field of view (pages 141-142). (d) For an object at infinity a concave mirror forms a point-sized, real image at the focus (page 138).

Question 4. Use the refractive indices in Table 9.3 (page 149): ruby 1.71, water 1.33, crown glass 1.52, and c = 3 × 10⁸ m/s. (a) What is the speed of light in ruby? (b) A ray passes obliquely from water into crown glass. Does it bend towards or away from the normal? (c) What is the refractive index of crown glass with respect to water, to two decimal places?

Answer: (a) about 1.75 × 10⁸ m/s; (b) towards the normal; (c) about 1.14. (a) n = c/v, so v = c/n = 3 × 10⁸ ÷ 1.71 ≈ 1.75 × 10⁸ m/s (page 149). (b) Crown glass has the larger refractive index, so it is optically denser; light slows on entering a denser medium and so bends towards the normal (page 149). (c) n(glass, water) = speed in water ÷ speed in glass = (c/1.33) ÷ (c/1.52) = 1.52/1.33 ≈ 1.14 (pages 148-149).

Question 5. From Table 9.3 (page 149): ice 1.31, alcohol 1.36 and benzene 1.50. (a) Which of the three is optically densest? (b) In which does light travel fastest? (c) What is the speed of light in benzene, taking c = 3 × 10⁸ m/s? (d) Benzene's mass density is lower than water's. Does that mean benzene is optically rarer than water (1.33)?

Answer: (a) benzene; (b) ice; (c) 2 × 10⁸ m/s; (d) no, it is optically denser. (a) The highest refractive index marks the optically densest of the three (page 149). (b) Light is fastest where the refractive index is smallest, since v = c/n (page 149): ice, at about 3 × 10⁸ ÷ 1.31 ≈ 2.29 × 10⁸ m/s. (c) v = c/n = 3 × 10⁸ ÷ 1.50 = 2 × 10⁸ m/s. (d) Optical density is not mass density: 1.50 > 1.33, so benzene is optically denser than water whatever its mass density, just as the book says of kerosene (page 149).

Question 6. A 3 cm tall object is placed 18 cm from a convex lens of focal length 12 cm. (a) Find the image distance. (b) Find the magnification and the image height. (c) Describe the image, and check it against the textbook's table for a convex lens.

Answer: (a) v = +36 cm; (b) m = −2, h′ = −6 cm; (c) real, inverted, enlarged, on the other side of the lens. (a) u = −18 cm and f = +12 cm (page 155). 1/v = 1/f + 1/u = 1/12 − 1/18 = (3 − 2)/36 = 1/36, so v = +36 cm. (b) m = v/u = 36/(−18) = −2 (page 156), so h′ = −2 × 3 = −6 cm. (c) The negative sign means real and inverted. The object is between F₁ (12 cm) and 2F₁ (24 cm), and Table 9.4 puts the image beyond 2F₂ (here 36 cm > 24 cm), enlarged, real and inverted (page 152).

Question 7. An object is placed 30 cm from a concave lens of focal length 20 cm. (a) Where is the image? (b) What is the magnification? (c) Could you catch this image on a screen?

Answer: (a) 12 cm from the lens, on the same side as the object; (b) +0.4; (c) no. (a) u = −30 cm and f = −20 cm (concave lens, page 155). 1/v = 1/f + 1/u = −1/20 − 1/30 = −5/60 = −1/12, so v = −12 cm: on the object's side. (b) m = v/u = (−12)/(−30) = +0.4 (page 156). (c) A positive m and an image on the same side mean a virtual, erect, diminished image, as a concave lens always gives (pages 153, 156); virtual images cannot be caught on a screen.

Question 8. (a) An eye prescription reads −1.25 D. What kind of lens is it, and what is its focal length in cm? (b) A reading lens has a focal length of +40 cm. What is its power? (c) If these two lenses were placed in contact, what would be the power and the focal length of the combination?

Answer: (a) concave, f = −80 cm; (b) +2.5 D; (c) +1.25 D, f = +80 cm (convex). (a) Negative power means a concave lens; f = 1/P = 1/(−1.25) = −0.8 m = −80 cm (pages 157-158). (b) P = 1/f = 1/0.40 m = +2.5 D. (c) Powers of lenses in contact add: −1.25 + 2.5 = +1.25 D, so f = 1/1.25 = 0.8 m = +80 cm, a convex (converging) combination (page 158).

Revise with questions

Test yourself next: Class 10 Light, 8 practice questions with answers. The other notes in this set: Electricity, Acids, Bases and Salts and Life Processes. For timed practice, the free Class 10 revision papers include a Science paper laid out in 1, 2, 3 and 5-mark sections.

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Sources

All checked on 4 November 2026. NCERT page numbers are the printed page numbers of the textbook (printed page = PDF page + 133).

The facts, formulas, section numbers and figure numbers are from the documents above. The wording of these notes, the diagram steps, the list of mistakes and the 8 questions are our own.

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