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Class 10 Human Eye and the Colourful World notes: NCERT Science Chapter 10 revision

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These are short revision notes for "The Human Eye and the Colourful World", Chapter 10 of the NCERT Class 10 Science textbook (Reprint 2026-27), pages 161 to 170. The chapter has two halves: the eye as a lens system with its three common defects, and what light does in a prism, in raindrops and in the air. These notes give a one-page summary table, then go section by section, and end with the key words, the diagram to practise, the common mistakes and 8 quick questions of our own with worked answers.

Keep the textbook open next to these notes. The wording here is our own; the textbook is the authority.

How much it counts

CBSE's Class 10 Science curriculum for 2026-27 puts this chapter in Unit III, Natural Phenomena, worth 12 of the 80 theory marks, shared with Light – Reflection and Refraction (curriculum, PDF page 4). For this chapter the unit lists how the lens works in the human eye, the defects of vision and how they are corrected, refraction through a prism, dispersion and scattering of light and their uses in daily life. It leaves out the Sun's colour at sunrise and sunset (PDF page 6). More on the units: CBSE Class 10 Science syllabus 2026-27.

The chapter on one page

TopicWhat to rememberPage
Near point (normal young adult)about 25 cm162
Far point (normal eye)infinity162
Myopiaimage of a far object falls in front of the retina; concave lens163
Hypermetropiaimage of a near object falls behind the retina; convex lens163
Presbyopianear point moves away with age; often bi-focal lenses163-164
Prismsplits white light; red bends least, violet most166-167
Rainbowalways on the side of the sky opposite the Sun167
Sun seen early and lateabout 2 minutes each way, from atmospheric refraction168
Blue skyfine particles scatter short (blue) wavelengths more169

1. The human eye (section 10.1, pages 161-162)

2. Accommodation, near point and far point (section 10.1.1, page 162)

3. Defects of vision and their correction (section 10.2, pages 162-164)

DefectCan see clearlyWhere the image fallsCausesCorrection
Myopia (near-sightedness)near things; far point closer than infinityin front of the retina, for a distant objectlens too curved, or eyeball too longconcave lens
Hypermetropia (far-sightedness)far things; near point beyond 25 cmbehind the retina, for a close objectfocal length too long, or eyeball too smallconvex lens
Presbyopianear point recedes with age—weaker ciliary muscles, less flexible lenscorrective glasses for near work; bi-focal lenses if myopia and hypermetropia come together

4. Refraction through a prism (section 10.3, pages 165-166)

5. Dispersion and the rainbow (section 10.4, page 167)

6. Atmospheric refraction (section 10.5, page 168)

7. Scattering of light (section 10.6, page 169)

Key words at a glance

The diagram to know: myopia and its correction

Board papers often ask for the eye-defect diagrams. Practise this three-part one (it follows Fig. 10.2):

  1. (a) Far point of a myopic eye: draw the eyeball as a circle with the lens near the front. Mark a point O a short way in front of it. Rays from O enter the eye and meet on the retina: O is the farthest point this eye sees sharply.
  2. (b) Myopic eye: draw parallel rays from a very distant object. They meet at a point in front of the retina and have spread out again by the time they reach it, so the image is blurred.
  3. (c) Correction: put a concave lens in front of the eye. The parallel rays leave it spreading out, as if they started at O (show this with dotted lines back to O). The eye can focus light from O, so the rays now meet on the retina.
  4. Label the three parts, and write "concave lens of suitable power" under (c).

For hypermetropia (Fig. 10.3), mark N (the defective near point) and N′ (the normal near point, 25 cm). Rays from an object at N′ meet behind the retina; a convex lens bends them so they seem to come from N, and the image lands on the retina.

Mistakes that cost marks

Quick check: 8 questions of our own

These are our own questions, written for these notes and checked against the textbook pages named; no practising teacher has reviewed them yet. Every number was re-computed by a script.

Question 1. (a) Roughly what shape and size is the human eyeball? (b) Where does most of the bending of the light happen? (c) After the image forms, what carries the information to the brain?

Answer: (a) nearly a sphere, about 2.3 cm across; (b) at the cornea, on its outer surface; (c) electrical signals along the optic nerves. (a) The book gives the eyeball as approximately spherical with a diameter of about 2.3 cm (page 161). (b) The book says the cornea's outer surface does most of the refraction; the lens only adjusts the focal length (page 161). (c) The retina's light-sensitive cells produce electrical signals that the optic nerves take to the brain (page 162).

Question 2. Use a simple model eye in which the lens sits a fixed 2.0 cm from the retina, so every sharp image has v = +2.0 cm. (a) What focal length does the lens need for a star (object at infinity)? (b) What focal length does it need for a page 25 cm away? (c) Which focal length is shorter, and what do the ciliary muscles do to get it? (d) Find the two powers and their difference.

Answer: (a) 2.0 cm; (b) 50/27 ≈ 1.85 cm; (c) the one for the page: the muscles contract; (d) +50 D and +54 D, a difference of 4 D. (a) With u at infinity, 1/u = 0, so 1/f = 1/v and f = 2.0 cm (lens formula, Chapter 9). (b) u = −25 cm: 1/f = 1/v − 1/u = 1/2 + 1/25 = 27/50, so f = 50/27 ≈ 1.85 cm. (c) To focus a near object the ciliary muscles contract, the lens becomes thicker and its focal length decreases (page 162). (d) P = 1/f in metres: 1/0.02 = 50 D and 27/0.5 = 54 D, so the eye adds 4 D. (The real eye is not this simple, since the cornea does most of the bending; the model only shows why the focal length must change.)

Question 3. Name the defect and the lens that corrects it for each person. (a) Kabir reads his book easily but cannot read the number on a bus until it is a few metres away. (b) Mrs Rao, 58, could read at 25 cm when young; now she holds the newspaper well beyond that, though she sees distant hills clearly. Her doctor says the cause is age. (c) Mr Singh would rather not wear spectacles at all. Name two other ways of correcting a refractive defect that the chapter mentions.

Answer: (a) myopia, concave lens; (b) presbyopia, reading glasses with a convex lens; (c) contact lenses, or surgery. (a) Clear near vision with a far point short of infinity is myopia; a concave lens of suitable power corrects it (page 163). (b) A near point that moves away with age, from weaker ciliary muscles and a less flexible lens, is presbyopia, and she needs corrective glasses to see near things (pages 163-164). Near vision is helped by a convex lens: it is the near-vision (lower) part of a bi-focal (page 164). (c) Besides spectacles, the book says refractive defects can now be corrected with contact lenses or through surgical interventions (page 164).

Question 4. An optometrist gives Meera distance glasses of power −0.5 D. (a) Is the lens concave or convex? (b) What is its focal length in cm? (c) For a distant object, this lens forms a virtual image at its focus, which is where Meera's far point must be. How far can she see clearly without glasses? (d) Name her defect.

Answer: (a) concave; (b) −200 cm; (c) about 2 m; (d) myopia. (a) Negative power means a diverging, concave lens (Chapter 9, page 158). (b) f = 1/P = 1/(−0.5) = −2 m = −200 cm. (c) For u at infinity, 1/v = 1/f, so v = −200 cm: the image sits 2 m in front of the eye, at her far point. (d) A far point nearer than infinity, corrected by a concave lens, is myopia (page 163).

Question 5. Arjun sees distant hills clearly, but the print of a book held at 25 cm looks blurred. His reading glasses are marked +2.5 D. (a) Name the defect. (b) Is the lens converging or diverging, and what is its focal length in cm? (c) How does Arjun's near point compare with the 25 cm of a normal young eye? (d) Why would these glasses not help someone who cannot see distant objects clearly?

Answer: (a) hypermetropia; (b) converging (convex), f = +40 cm; (c) it is farther than 25 cm; (d) that person has myopia, which needs a diverging (concave) lens. (a) Seeing far objects clearly but not near ones is hypermetropia, or far-sightedness (page 163). (b) Positive power means a converging, convex lens (Chapter 9, page 158): f = 1/P = 1/2.5 m = 0.4 m = 40 cm, and a convex lens is what the book prescribes for this defect (page 163). (c) For hypermetropia the near point is farther away than the normal near point of 25 cm (page 163). (d) Not seeing distant objects is myopia, which is corrected with a concave lens of suitable power, not a convex one (page 163).

Question 6. In a diagram, a ray KL strikes face AB of a triangular glass prism ABC at L, travels through the glass along LM, and leaves through face AC at M along MN. (a) Which of KL, LM and MN is the incident ray, which is the refracted ray, and which is the emergent ray? (b) At L the ray goes from air into glass, and at M from glass into air. At each point, does it bend towards the normal or away from it? (c) If the same ray were sent through a rectangular glass slab instead, how would the ray coming out be directed compared with the ray going in?

Answer: (a) KL incident, LM refracted, MN emergent; (b) towards the normal at L, away from it at M; (c) parallel to the ray going in, only shifted sideways. (a) KL strikes the first face, so it is the incident ray; LM travels inside the glass, so it is the refracted ray; MN leaves the second face, so it is the emergent ray. They match PE, EF and FS in the book's figure (page 166). (b) Light passing into a denser medium, air to glass, bends towards the normal at the first face; passing out into a rarer medium, glass to air, it bends away from the normal at the second face (page 166). (c) A slab's two refracting faces are parallel, so the ray coming out runs parallel to the ray going in, just shifted a little to one side (page 165).

Question 7. (a) At 5 pm, with the Sun low in the west, a shower passes. Which part of the sky should you watch for a rainbow? (b) At 8 am you water the garden with a hose spray. Where should the Sun be for you to see a rainbow in the spray? (c) Put in order what happens to sunlight in a raindrop: internal reflection; refraction and dispersion on entering; refraction on leaving.

Answer: (a) the east; (b) behind you; (c) refraction and dispersion on entering, internal reflection, refraction on leaving. (a) A rainbow always forms opposite the Sun, so with the Sun in the west look east (page 167). (b) The book notes rainbows in waterfall or fountain spray when the Sun is behind the viewer (page 167). (c) Droplets refract and disperse the light, reflect it inside, then refract it again as it leaves (page 167).

Question 8. Name the effect behind each: (a) the beam from a cinema projector shows up in the dusty air of the hall; (b) clouds, made of fairly large water droplets, look white; (c) the far side of a hot tandoor seems to shimmer when you look across the top of it; (d) a star low over the horizon looks slightly higher than its real position.

Answer: (a) scattering (Tyndall effect); (b) scattering by large particles; (c) atmospheric refraction; (d) atmospheric refraction. (a) Fine particles in the air scatter the light, making the beam's path visible (page 169). (b) When scattering particles are large enough, the scattered light can look white (page 169). (c) The hot air above the tandoor has a slightly lower refractive index than the cooler air higher up and keeps moving, so the apparent position wavers (page 168). (d) The atmosphere bends starlight towards the normal, so the star appears above its true position (page 168).

Revise with questions

Test yourself next: Class 10 Human Eye and the Colourful World, 8 practice questions with answers. Free practice on this chapter, marked instantly in your browser: Class 10 Human Eye and the Colourful World questions. The chapter before this one: Class 10 Light, 8 practice questions with answers. The other notes in this set: Electricity, Acids, Bases and Salts and Life Processes. For timed practice, the free Class 10 revision papers include a Science paper laid out in 1, 2, 3 and 5-mark sections.

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Sources

All checked on 4 November 2026. NCERT page numbers are the printed page numbers of the textbook (printed page = PDF page + 160).

The facts, section numbers and figure numbers are from the documents above. The wording of these notes, the diagram steps, the list of mistakes and the 8 questions are our own.

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