Learn
Class 9 Science: Atomic Foundations of Matter, 8 practice questions with answers
These are 8 practice questions on Chapter 9, Atomic Foundations of Matter, of the new NCERT Class 9 Science textbook, Exploration (First Edition, April 2026). Each has a worked answer and the textbook page it comes from. They cover the law of conservation of mass, the law of constant proportions, a single covalent bond, writing the formula of an ionic compound by criss-crossing, naming and finding the molecular mass of a covalent compound, the formula unit mass of an ionic compound, and why ionic compounds conduct only in solution. Try each one on paper before you open the answer.
These questions are our own, drafted with AI help. Every number was re-computed by a test script and none of the numbers is taken from the chapter, but no practising teacher has reviewed them yet. If you find a mistake, please tell us.
Atomic masses are the ones the textbook uses: H = 1 u, N = 14 u, O = 16 u, K = 39 u (pages 179 and 180).
What the chapter says you need
Facts from the NCERT textbook (Exploration: Textbook of Science for Grade 9, Chapter 9, printed pages 162 to 183):
- Law of Conservation of Mass: matter can neither be created nor destroyed in a chemical reaction; the total mass stays the same before and after (page 165).
- Law of Constant (Definite) Proportions: in a compound, the elements always combine in a fixed ratio by mass, whatever the source or method of preparation (page 167).
- In a covalent bond, atoms share electrons; one shared pair is a single covalent bond, as in hydrogen chloride, H—Cl (page 171).
- Covalent compounds are named with prefixes for the number of atoms (mono, di, tri, ...); the second element ends in -ide (page 172).
- Table 9.1 gives the charges (valencies) of common ions, for example Al³⁺, S²⁻, K⁺ and the nitrate ion NO₃⁻ (pages 174 and 175). To write the formula of an ionic compound, criss-cross the charges and reduce to the simplest ratio (page 176).
- Ionic compounds do not conduct electricity in the solid state, because their ions are held in fixed positions; dissolved in water, the ions are free to move and the solution conducts (page 178).
- Molecular mass is the sum of the atomic masses of all the atoms in a molecule (page 179). For an ionic compound, the sum over one formula unit is the formula unit mass (pages 179 and 180).
Laws of chemical combination
Question 1. In a sealed flask, 17.5 g of one substance reacts completely with 6.3 g of another. No gas can escape. What is the total mass of the products?
Answer: 23.8 g. Mass is neither created nor destroyed in a chemical reaction, so the products have the same total mass as the reactants: 17.5 + 6.3 = 23.8 g. (Law of Conservation of Mass, page 165.)
Question 2. In a certain compound, elements X and Y always combine in the mass ratio 5 : 7. How much of Y combines completely with 45 g of X?
Answer: 63 g. The ratio is fixed, so Y = 45 × 7/5 = 63 g. Check: 45 : 63 = 5 : 7. (Law of Constant Proportions, page 167.)
Question 3. One student collects carbon dioxide from burning charcoal; another collects carbon dioxide from the reaction of baking soda with vinegar. Will the mass ratio of carbon to oxygen be the same in both pure samples? Which law says so?
Answer: yes, the same; the Law of Constant (Definite) Proportions. A pure compound always has its elements in the same fixed ratio by mass, whatever its source or the way it was made. (Page 167.)
Bonds, formulae and names
Question 4. Hydrogen bromide is HBr. Hydrogen needs one electron and bromine (seven valence electrons) needs one electron to be stable. How many electrons does each atom share, and what kind of bond forms?
Answer: each atom shares one electron, forming one shared pair: a single covalent bond, H—Br. This is the same pattern the textbook shows for hydrogen chloride. (Covalent bond in HCl, page 171.)
Question 5. Using Table 9.1, aluminium forms Al³⁺ and sulfur forms the sulfide ion S²⁻. Write the formula of aluminium sulfide.
Answer: Al₂S₃. Write the charges, 3+ for Al and 2− for S, and criss-cross them: Al gets 2 and S gets 3. The subscripts 2 and 3 have no common factor, so the formula is Al₂S₃. Check: 2 × (+3) = +6 and 3 × (−2) = −6, so the compound is neutral. (Table 9.1, page 174; criss-crossing, page 176.)
Question 6. A covalent compound has the formula N₂O₃. Name it and find its molecular mass.
Answer: dinitrogen trioxide; 76 u. Two nitrogen atoms (di) and three oxygen atoms (tri, ending in -oxide). Molecular mass = (14 u × 2) + (16 u × 3) = 28 u + 48 u = 76 u. (Naming covalent compounds, page 172; molecular mass, page 179.)
Masses and properties
Question 7. Find the formula unit mass of potassium nitrate, KNO₃.
Answer: 101 u. One formula unit has one K, one N and three O: (39 u × 1) + (14 u × 1) + (16 u × 3) = 39 + 14 + 48 = 101 u. (Formula unit mass, pages 179 and 180; the nitrate ion, Table 9.1, page 175.)
Question 8. A crystal of an ionic compound does not let a bulb glow in a conductivity test, but its solution in water does. Explain why.
Answer: In the solid crystal, the ions are held in fixed positions by strong forces, so they cannot move and carry a current. When the compound dissolves in water, the ions become free to move, so the solution conducts electricity. (Properties of ionic compounds, page 178.)
Practise more, and check your marks
- Free practice, marked instantly in your browser: Class 9 Atomic Foundations of Matter questions, a separate short set on the same chapter.
- Printable Class 9 worksheets with answer keys, in English, Hindi and Marathi: Class 9 worksheets.
- The chapter on the atom itself: Class 9 Journey Inside the Atom, practice questions.
- Where chemical formulae go next, in Class 10: Chemical Reactions and Equations and Acids, Bases and Salts.
Where CMDLearn fits
CMDLearn is building an AI tutor for Classes 1 to 10 that explains a step and checks the child's working, but leaves the writing to the child. It is still in development, and no child uses it yet. If you would like to hear when there is something to try, you can join the waitlist.
Sources
All opened and read on 21 October 2026. Page numbers are the printed page numbers of the textbook; printed page = PDF page + 161.
- NCERT, Exploration: Textbook of Science for Grade 9 (First Edition, April 2026), Chapter 9 "Atomic Foundations of Matter", printed pages 162-183 (Law of Conservation of Mass, page 165; Law of Constant Proportions, page 167; the covalent bond in hydrogen chloride, page 171; naming covalent compounds, page 172; Table 9.1 of ions and valencies, pages 174-175; writing formulae of ionic compounds, page 176; properties of ionic compounds, page 178; molecular mass and formula unit mass, pages 179-180): ncert.nic.in/textbook/pdf/iesc109.pdf
- NCERT, Exploration: Textbook of Science for Grade 9, front matter and contents (chapter titles and starting pages): ncert.nic.in/textbook/pdf/iesc1ps.pdf
The laws, rules and atomic masses are from the textbook pages above. The questions, worked answers and checks are our own, and every number was re-computed by script. This guide is general information; follow your teacher and the textbook.