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Class 7 Maths: Connecting the Dots, 8 practice questions with answers

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These are 8 practice questions on Chapter 5, Connecting the Dots…, of the new NCERT Class 7 Maths textbook, Ganita Prakash, Part 2. Each has a worked answer and the textbook page it comes from. They cover telling statistical questions apart, the mean as a fair share, the score needed to raise a mean, the median of odd and even lists, outliers, a zero reading against a broken rain gauge, how late the school bus was, and reading two sets of data side by side. Try each one on paper before you open the answer.

These questions are our own, drafted with AI help. Every number was re-computed by a test script and none of the chapter's own data is reused, but no practising teacher has reviewed them yet. If you find a mistake, please tell us.

What the chapter says you need

Facts from the NCERT textbook (Ganita Prakash, Grade 7, Part 2, Chapter 5, printed pages 97 to 135):

Questions and means

Question 1. Each of these questions has just one answer, so it is not a statistical question: (a) How old is my grandmother? (b) What time did I wake up today? Rewrite each one as a statistical question, and say what data you would collect to answer it.

Answer: for example, (a) 'How old are the grandmothers of the children in our class?' (b) 'At what times do the children in our class wake up on school days?' A statistical question needs data that varies, so it must be about many people, days or things, not just one. (a) Asking about the grandmothers of all the children in the class gives many different ages; we would collect each grandmother's age and then describe them, for example with the mean and the range. (b) Asking about everyone's wake-up time on school days (or about my own wake-up time over a month) gives many different times; we would note each time and look at how they spread out. Other answers are fine if they ask about many values that vary. (Statistical questions, pages 97 and 98.)

Question 2. Six friends have saved ₹46, ₹33, ₹57, ₹29, ₹64 and ₹41. If they put the money together and share it equally, how much does each get? What is this number called?

Answer: ₹45 each; this is the mean. The total is 46 + 33 + 57 + 29 + 64 + 41 = ₹270. Shared equally among 6 friends, each gets 270 ÷ 6 = ₹45. This fair share is the mean (average) of the savings. (The mean as a fair share, pages 99 to 101.)

Question 3. Asha's mean score over 4 tests is 73. What must she score in her 5th test to raise her mean to 75?

Answer: 83. A mean of 73 over 4 tests means her total so far is 4 × 73 = 292. For a mean of 75 over 5 tests she needs a total of 5 × 75 = 375. So the 5th test must give 375 − 292 = 83. Check: (292 + 83) ÷ 5 = 375 ÷ 5 = 75. (The mean, pages 99 to 101.)

Medians and outliers

Question 4. Seven parcels weigh 2.4, 3.6, 1.7, 6.3, 2.7, 3.3 and 2.1 kg. (a) Find the median weight. (b) An eighth parcel of 4.0 kg arrives. What is the median now?

Answer: (a) 2.7 kg; (b) 3.0 kg. (a) Sort the weights: 1.7, 2.1, 2.4, 2.7, 3.3, 3.6, 6.3. With 7 values, the middle one is the 4th, so the median is 2.7 kg. (b) With 8 values (1.7, 2.1, 2.4, 2.7, 3.3, 3.6, 4.0, 6.3) there are two middle values, 2.7 and 3.3. The median is their mean: (2.7 + 3.3) ÷ 2 = 3.0 kg. (The median, page 106.)

Question 5. A snack stall took ₹430, ₹390, ₹470, ₹415 and ₹2950 on five days; the last day was a festival. (a) Find the mean and the median. (b) Which describes a typical day better, and why? (c) What are the mean and median of the other four days?

Answer: (a) mean ₹931, median ₹430; (b) the median; (c) mean ₹426.25, median ₹422.50. (a) The total is ₹4655, so the mean is 4655 ÷ 5 = ₹931. Sorted, the takings are 390, 415, 430, 470, 2950, so the median is ₹430. (b) The festival day is an outlier. It pulls the mean up so far that only one day (the festival) took more than the mean, so ₹931 does not describe an ordinary day. The median stays close to the ordinary days. (c) Without the festival day the total is 1705, so the mean is 1705 ÷ 4 = ₹426.25, and the median is (415 + 430) ÷ 2 = ₹422.50: now the two are close. (Outliers and medians, pages 106 to 108.)

Question 6. A school's rain gauge recorded these amounts on 7 days, in mm: 12, 0, 7, (gauge broken), 4, 0, 19. Find the mean daily rainfall for the days on which the gauge worked.

Answer: 7 mm a day. The two 0 mm days are real readings (the gauge worked and no rain fell), so they count. The day the gauge was broken has no value at all, so it is left out. That makes 6 days with readings, totalling 12 + 0 + 7 + 4 + 0 + 19 = 42 mm, and the mean is 42 ÷ 6 = 7 mm a day. Dividing by 7 would wrongly count the broken day as a reading of 0. (Zero versus no value, page 111.)

Describing and comparing data

Question 7. On nine school days the bus was this many minutes late: 0, 3, 2, 8, 3, 1, 3, 5, 2. Find the range, the mean and the median, and say on how many days the bus was later than the mean.

Answer: range 8 minutes, mean 3 minutes, median 3 minutes; on 2 days it was later than the mean. The smallest value is 0 and the largest 8, so the range is 8 − 0 = 8 minutes. The total is 27, so the mean is 27 ÷ 9 = 3 minutes. Sorted: 0, 1, 2, 2, 3, 3, 3, 5, 8, so the median (5th value) is 3 minutes. The bus was later than 3 minutes only on the days it was 5 and 8 minutes late: 2 days. (Minimum, maximum and mean, pages 99 to 102; the median, page 106; the range, page 134.)

Question 8. Two shops sold these numbers of loaves from Monday to Friday. Shop A: 33, 42, 27, 46, 37. Shop B: 35, 40, 31, 49, 43. (a) On how many days did Shop B sell more? (b) On which day was the gap largest? (c) Compare the totals, means and medians. (d) In a double bar graph of this data, what scale would suit?

Answer: (a) 4 days; (b) Friday, by 6 loaves; (c) totals 185 and 198, means 37 and 39.6, medians 37 and 40; (d) 1 unit = 10 loaves. (a) Shop B sold more on Monday, Wednesday, Thursday and Friday; only on Tuesday did Shop A sell more (42 against 40). (b) The differences B − A are 2, −2, 4, 3 and 6, so the largest gap is on Friday. (c) Shop A sold 185 loaves (mean 185 ÷ 5 = 37, median 37), and Shop B sold 198 (mean 198 ÷ 5 = 39.6, median 40), so Shop B did a little better on every measure. (d) All values are below 50, so marking the vertical line in steps of 10 up to 50 keeps the bars readable, with the two shops' bars side by side for each day. (Double bar graphs and comparing data, pages 114 to 117.)

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Sources

All opened and read on 1 November 2026. Page numbers are the printed page numbers of the textbook; printed page = PDF page + 96 for this chapter.

The rules are from the textbook pages above. The questions, worked answers and checks are our own, and every number was re-computed by script. This guide is general information; follow your teacher and the textbook.